are u talking about that "loser" game question?
a) loser is decided in the very first game ==> exactly one gets a head or exactly one gets a tail.
P(finding a loser)=
nC1pq^n-1 + nC1qp^n-1 where q=1-p
b)
P(not finding a loser)= no exact 1 head OR no exact 1 tail.
= 1 - nC1pq^n-1 + 1 - nC1qp^n-1
= 2 - nC1pq^n-1 - nC1qp^n-1
P(finding a loser in kth trial)= P(no loser till k-1 trials and a loser in kth trial)
= {[2 - nC1pq^n-1 - nC1qp^n-1]^(k-1)} * {nC1pq^n-1 + nC1qp^n-1}
I hope i didnt miss anything.
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"You don't have to believe in God, but you should believe in The Book." -Paul Erdős