DSE 2005 stats doubt

[MR]

http://economicsentrance.weebly.com/uploads/1/1/0/5/1105777/25_jun_2005_option_a.pdf
Question no.19.  

[Sinistral]

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[MR]

Hey Sinistral I meant the question next to this one. This was the 18th question I guess. Let me know if you can solve that. :)

[Sinistral]

uff ab ques no. padne me bhi mujhse galti ho rhi hai.  

19)
P(X^2>1 and Y^3<-1)
=P(X^2>1)*P(Y^3<-1)   --- since X and Y are independent
=P(X<-1 or X>1)*P(Y<-1)
=[P(X<-1)+ P(X>1)]*P(Y<-1)
=[P(X<-1) + P(X<-1]*P(Y<-1)   using property of N(0,1) distribution which is symmetric about x=0.
=[p+p]*p                               since X and Y are iid and P(X<-1) =p (given)
=2p^2

[MR]

Haha don't worry. You will be all good on 29th. :)