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DSE 2006

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DSE 2006

Unsure M
Can anyone please explain the solution for Q 37 of the 2006 paper?? I'm kinda confused about the answer.....pleaseeee
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Re: DSE 2006

Sinistral
to find the vertical asymptotes set denominator =0 ==> x=0 ==> y axis is the vertical asymptote.

oblique asymptote:
(x^2+2x-1)/x
= x+2 - (1/x)
when x --> infinity the above function tends to x+2 ==> y=x+2 is the other asymptote.

so option c
---
 "You don't have to believe in God, but you should believe in The Book." -Paul Erdős
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Re: DSE 2006

Unsure M
thnx a ton sinistral :)