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DSE 2009
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Ashima
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Jun 17, 2011; 4:34pm
DSE 2009
7 posts
Hi Sir,
Can you please explain how I should solve this problem?
Consider tow events A and B with P(A) = 0.4 and P(B) = 0.7. The maximum and minimum values of P(A intersection B) respectively are:
a. 0.4, 0.1
b. 0.7, 0.4
c. 0.7, 0.1
d. 0.4, 0
PRIYANKA
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Jun 17, 2011; 6:39pm
Re: DSE 2009
5 posts
hi ashima
P(AUB) = P(A) + P(B) -P(A INTERSECTION B)
= 0.4 +0.7 -P(A INTERSECTION B)
=1.1- P(A INTERSECTION B)
SO MIN VALUE IS .1
AND p(A) = 0.4 , p(B) = 0.7
SO MAX VALUE IS .4
Ashima
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Jun 19, 2011; 3:29pm
Re: DSE 2009
7 posts
Hi Priyanka,
Thanks for the reply:)
I did not understand how did you get max value equal to 0.4?
Amit Goyal
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Jun 19, 2011; 6:09pm
Re: DSE 2009
Administrator
775 posts
Its simple. A INTERSECTION B is a subset of both A and B and hence P(A INTERSECTION B) can take value less than or equal to min{P(A), P(B)} = 0.4. The max value it can take is thus 0.4.
Ashima
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Jun 20, 2011; 8:01am
Re: DSE 2009
7 posts
Thank you sir:)
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