Q48) Integrate kx over [0,5], k*(10-x) over [5,10] and equate the sum equal to 1, you will get an equation of the form, k*(25/2)+{(100*k-50*k-50*k+(25/2)*k}=1,
or, k*25=1,
or, k=1/25.
Q49) P(AGivenB)=Pr(X>=5 intersection X=[3,5])/Pr(X=[3,5])={integration (1/25)*(10-x) over [5,8]}/{integration (1/25)*x over [3,5]+(1/25)*(10-x) over [5,8]} from this the numerator will be (21/50) and the denominator will be (37/50), hence the required probability will be (21/37).
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