DSE 2010 doubts

[Halflife]

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[AdityaGarg13]

For first question,

find pdf...

For n=1, as it is uniformly distributed it is at mid point = 1/2.

For n =2, its values would be at 1/3 and 2/3. Maximum would be 2/3.

For n=3, its value would be at 1/4, 2/4, and 3/4.  Maximum would be 3/4.

Similarly for other values of n.

Hence this expected maximum value turns out to be n/n+1

[Halflife]

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[Rajesh]

calculate profit in each case,
p1 cannot be 2 in any case, it will suffer loss otherwise,
profit2 is coming out to be same whether we take p2=2 or p2=3

Hence its option d

[Halflife]

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