DSE 2011 Q 56

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DSE 2011 Q 56

Khagesh
Hey temme how to solve Q56 i.e. find Rate of Growth of aggregate output in steady state for Solow Model?????????
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Re: DSE 2011 Q 56

sunny2009
......... Y=20(K)^0.5*(L)^0.5
       DIVIDING BY L BOTH SIDES
        Y/L=20(K/L)^0.5
      OR y = 20(k)^0.5
      or  f(k)= 20 (k)^0.5

in steady state,
sf(k)-nk equals 0.
or,sf(k)=nk (equation 1)

it is given that n=1/10 AND s=1/4
PUTTING THE VALUES...in the above equation
1/4*20(K)^0.5 = 1/10*K
U WILL SOLVE N GET THE VALUE OF K AS 2500.
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Re: DSE 2011 Q 56

Khagesh
I need for Q 56...
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Re: DSE 2011 Q 56

sunny2009
In reply to this post by Khagesh
for ques 56.......
rate of growth of aggregate output in the steady state is equal to the rate at which the labour force grows...
hence the answer will be 1/10
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Re: DSE 2011 Q 56

Khagesh
thnx man :)

dre r oder doubts ive posted too.... plz c if u can solve dem too
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Re: DSE 2011 Q 56

sunny2009
welcome buddy :)
i will try my best to solve them...........