DSE 2012- Question 42-44, 48 and 55-56.

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Re: DSE 2012- Question 42-44, 48 and 55-56.

duck
Hey Sinistral.. :)

Area of rectangle is (x)(x^2+1/x^2)
For the above expression to be zero, either (x=0) or (x^2+1/x^2 = 0) and we can never make anyone of them equal to zero.
Plot x^2+1/x^2, you'll see 'as x tends to zero, it tends to infinity'.

:)
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Re: DSE 2012- Question 42-44, 48 and 55-56.

Sinistral
But in "Area of rectangle is (x)(x^2+1/x^2)": aren't we assuming that one side is the x axis? the only thing given in question is a diagonal?

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 "You don't have to believe in God, but you should believe in The Book." -Paul ErdÅ‘s
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Re: DSE 2012- Question 42-44, 48 and 55-56.

duck
Corresponding to some value of "x" , we've that upper right hand corner as "x^2+1/x^2" and the lower left hand corner is the origin.
So, its like one side is "x" and other side would be x^2+1/x^2.
Refer the graph once.
Dse.png
:)
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