DSE 2013 Doubts

[SoniaKapoor]

q1= a+bP2(e)-c/2
how did the sign of bp2(e) become positive after the last step.?

[ViV]

Q7

[xyz123]

Hey can you explain 29.. Here's my explanation:

In question 28, allocation of (0,5,4) would be rejected(in future) as there would be 2 Yes and 1 No. As this is the proposal of 2, then allocation of (3,3,3) will be implemented. So in question 29, if a) is implemented i.e. (5,0,4) because individual 3 knows that even if he will reject this and accept b), from proposal of individual 2 he will ultimately get an allocation of (3,3,3). Thus would be worse off.

Kindly tell where I'm going wrong

[xyz123]

And for 30th, according to me answer should be a) and not c), as in a) individual 1 would choose allocation (4,5,0) instead of (3,3,3) as he is made better off.. :/

[The Villain]

Pls explain quest 38..ecotrix one

[Dreyfus]

IMG_20140619_130017.jpg
Q58 ecotrix series 04 2013

[The Villain]

Thanx Vaibhav bt by mistake i wrote 2013, not in that  
actually the quest is

[ViV]

Return = 1st derivative of main function
Return's derivative = 2nd order derivative of main function which is<0

[Dreyfus]

In this question both experience nd experience ² are statistically significant (as t values are too high nd enough to reject null hypothesis that coefficient of exp (or exp²) =0). So take the first derivative  nd second derivative nd since second derivative is negative. Therefore returns to experience are strictly diminishing!

[Aranya]

DSE 2013 36,37,38.need help!

[Akshay Jain]

Solution to 38
suppose that A's utility function is U(d)a=da and utility function of B is U(d)b=db
where da = |plant location in [0,1] - 0.2| and db = |plant location in [0,1] - 0.7|

If the plant is at extreme position say 0 den da= 0.2, db=0.7 and when plant is at extreme position 1 dn da=0.8, db=0.3

now take a plant location in interval (0,0.2) dn
da<0.2 and db<0.7, so both of them are worse off (position 0 pareto dominates (0,0.2)

similarly take a plant location in interval (0.7,1) dn
da<0.8 and db<0.3, so both of them are worse off (position 1 pareto dominates (0.7,1)
therefore option (a) is ruled out

now take a location 0.5 dn
da=0.3 and db=0.2 which means utility of A increases but dat of B decreases when compared with location 0 but it is pareto dominated by location 1 so option b and c are also ruled out


hence option D

[ViV]

36

[ViV]

36

[ViV]

37

[Aranya]

thank u guys!

[Aranya]

DSE 2010 qsn 24.stuck.plz help

[Akshay Jain]

http://discussion-forum.2150183.n2.nabble.com/DSE-2010-td6390201.html
visit this thread...it vl help u....

[Gayyam]

Hi Akshay,

For the 38th question, if I take a location in [0.2,0.7], then I can't choose any other location that increases one's utility without making the other one worse off. Isn't that Pareto optimal?

eg. at dn=0.5, da=0.3, db=0.2. At dn =(0.5+∂), da=0.3+∂, db=0.2-∂. Thus, we can't make anyone better off without reducing the other's utility.

[Akshay Jain]

Hi Gayyam...
in the interval [.2,.7]....we get a location 0.5 which is dominated by locatoion 1 so we cant say that the entire interval [.2,.7] is pareto optimum.....

[Gayyam]

Ok. Thank you!