Administrator
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Probability that train 2 arrives before train 1 = ∫ P (train 2 arrives before t | train 1 arrives at t) P (train 1 arrives at t)dt
for t < 10, P (train 2 arrives before t | train 1 arrives at t) = 0
for 10 < t < 30, P (train 2 arrives before t | train 1 arrives at t) = (1/20)(t - 10)
Integrating from 10 to 30, ∫(1/20)(t - 10)(1/30) dt = [(1/600)(sq(t)/2-10t)] = 1/4 + 1/12 = 1/3
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