Discussion Problem_(18)

[duck]

Q1) Suppose the probability density function(pdf) of a random variable X is given by:
f(x) = kx(2-x) for 0≤x≤2
      = 0 otherwise.
Find "k" and mean of X.

Q2) There are 6 boys and 6 girls.In how many ways can they sit together in a ROW such that boys and girls sit alternately.

Q3) There are 6 boys and 6 girls. In how many ways can they sit together in a CIRCLE such that no two girls are together.

[Devika]

1)k=3/4 and mean=1

2) 6! * 6! * 2

[vandita24x7]

2) 7P6* 6! 

On Mon, May 27, 2013 at 10:12 PM, Devika [via Discussion forum] <[hidden email]> wrote:

1)k=3/4 and mean=1

2) 6! * 6! * 2

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NAML

[vandita24x7]

3) 5! * 6!

On Mon, May 27, 2013 at 10:52 PM, vandita 24x7 <[hidden email]> wrote:

2) 7P6* 6! 

On Mon, May 27, 2013 at 10:12 PM, Devika [via Discussion forum] <[hidden email]> wrote:

1)k=3/4 and mean=1

2) 6! * 6! * 2

---

If you reply to this email, your message will be added to the discussion below:

http://discussion-forum.2150183.n2.nabble.com/Discussion-Problem-18-tp7581348p7581350.html

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[Mauli]

q1 and q2 same as devika.
q3)6 boys can be arranged in a circle in 5! ways
no two girls sit together. implies boys and girls alternate each other. so girls can be arranged in 6! ways.
reqd ans 5!*6!

[Sumit]

1.k=3/4 n mean=1
2.(6!*6!)*2
3.5!*6!

[diptendra1991]

1. k=3/4; mean=1
2. (6!)(7!)
3. (6!)(6!)

[duck]

Cool.. :)
Correct Answers:
1) k=3/4 n mean=1
2) 6!*6!*2
3) 5!*6!