3.53plot the domain. plot x+y>1/2. overlapping region is our area of interest:
P(X+Y>1/2)= Integral (y=1/2 to 1) Integral (x=0 to y) f(x,y) dx dy + Integral (x = 0 to 1/4) Integral (y=1/2 -x to 1/2) f(x,y) dy dx + Integral (x = 1/4 to 1/2) Integral (y=x to 1/2) f(x,y) dy dx
Do you want to match your answer? because I haven't solved the above integral yet.
3.49Given: 0<x<1
Given: -x<y<x ==> y <|x|
since x is always positive we will take that portion of the graph y<|x| which is in first quadrant.
so, Integral (x= 0 to 1) Integral (y=0 to x) kx(x-y) dy dx =1
k= 8
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