Doubt

[Halflife]

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[Abhitesh]

XY = X if Y=1
     = -X if Y=-1.

X/Y = X for any Y.

Now the value of XY will depend on X/Y. If X/Y = x then XY = x or -x with equal probability.

[Halflife]

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[Sachin Sehgal]

But why X/Y is X ..I mean it's value should also be x or -x depending upon the value of Y.

[Abhitesh]

X|Y is the value of X given Y.
The value of X doesn't depend on Y.

[Halflife]

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[Abhitesh]

In that case they would be equal.

[AdityaGarg13]

I too think so. If it was X given by, it would have been enclosed in bracket.

Other term is product, this one would be division!!!

[Halflife]

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[Halflife]

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[sneha]

only if I assume X to be independent ....I'm able to solve the question

otherwise this is getting complicated

[Halflife]

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[sneha]

hey,as per what I read cov(x,y)=E(XY)-E(X)E(Y)

and acc to this it will become E(XY.X/Y)-E(XY)*E(X/Y)

[Halflife]

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[Shree]

Cant it be solved like this:
 
Let y=1
Z=X+X
   =2X
V(Z)=4V(X)


Let y=-1
Z=-X-X
   =-2X
V(Z)=4V(X)

And in both the cases  V(Z)>V(X)

If this is not the correct way then please explain why it isnt..:-)

[Halflife]

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