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Halflife
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Jun 29, 2017; 3:19pm
Doubt
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AmyDunne
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Jun 29, 2017; 3:48pm
Re: Doubt
X1 will use all K, so l1 = (X1^2)/K
l2 = X2^2
L=l1 + l2 = (X2^2) + (X1^2)/K
So, L*K= K(X2^2) + (X1^2)
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Jun 29, 2017; 4:12pm
Re: Doubt
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