Dse 2010 doubt .Help.

[Aish]

Que.45. Suppose 10 athletes are running in a race and exactly 2 of them are taking banned drugs.An investigator randomly selects 2 athletes for drug testing.What is the probability that neither of the cheaters will be caught.

[The Villain]

I'm getting 28/45..

[Granpa Simpson]

Total sample space = 10C2.
No of Elementary events=select 2 from those who havent doped=8C2.
Required Probability=8C2/10C2=28/45.

[Dreyfus]

P(neither of the cheaters will caught) = 1- p( atleast 1 of the cheater will caught)
P(atleast 1 of the cheater will caught) = p( both are cheater) + 2p(exactly one is cheater)

[Aish]

Thanks guys! :')

[Aranya]

Qsn no 43-46 same paper,need help!

[Aranya]

http://economicsentrance.weebly.com/uploads/1/1/0/5/1105777/option-a-2010.pdf

[Granpa Simpson]

For question number 43 answer will be a..this you can get by comparing the real wage that will lead to zero labor supply..the labor supply equation is given by Ls=-γ+δ*(W/P), from this you can get the wage rate at which labor supply=0 which comes out to be (W/P)=γ/δ.
Now since at this wage rate Ls=0 so wage rate cannot decline, it has to increase, in order to increase labor demand the MP(L)>real wage rate at zero labor supply which means β>γ/δ, this is the only condition which will lead to higher demand for labor leading to higher wage rates which will increase the labor supply from 0 to equilibrium.

[Aranya]

thanks,got it!

[mrittik]

but what approach for the other problems? 44, 45?