Dse2011 question

[Ansh malhotra]

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[Ansh malhotra]

[Ansh malhotra]

Options of above question are as follows:
1) 1
2) 2
3) n-1
4) none of the above

[knowpraveen]

For n=2, let the relation be a1v1+a2v2=0 which goes on to mean that (1)v1+(a2/a1)v2=0 which means there are two scalars. That's the minimum number of nonzero scalars possible in such an equation.

Forgot to add that this is the same for any value n since all other scalar values could be taken as zero.

[Ansh malhotra]

ThAnks. In pic they have written at least one c should be different from zero here c1 and c2 both should be different from zero

[knowpraveen]

One c different from zero is impossible. What does it mean? It means, c1v1+0.v2+0.v3+... which is 0 unless and until v1 is zero. Hence, there should be atleast two non-zero values of c. I hope its clear.