Econometrics-Gujrati problem

[kangkan]

Y^=0.2033+0.6560Xi
Se     0.0976        0.1961

r^2=.397  RSS=0.0544  ESS=0.0358

Y=labot force particiaption of women in 1972 and X=LFPR in 1968

Suppose LFPR in 1968 was 0.58.Establsih a 95% confidence interval of the mean of LFPR in 1972

Thanks in advance

[The Villain]

hey kangkan
We use forecasting for such questions.
Y0 hat +- t value*se (Y0 hat)

where Y0 hat is b1+b2X0=0.2033+0.6560*.58
=.5838

Now substitue Y0 hat value and se values....u will get ur confidence interval :)

[kangkan]

Hi ron..can you please show me how to derive the formula?

Thanks :)