i did it this way
p(efficient)=.25 p(inefficient)=.75
p(sold/efficient)=.8 p(sold /inefficient)=.4
revenue 10000 if was machine is sold
profit =1000*p(sold)-100
p(sold)=P(efficient)*p(sold/efficient)+p(sold /inefficient)=.5
therefore profit =400
and bonus should be higher than 10% i guess..
Hi...here is my take..the firm will maximize profit when the workers self select..hence it must but t such that inefficient people are not attracted and efficient are..
for an inefficient E(earning)= 0.4*1000*t/100..this must be less than 80.this gives t=20....now at t=20 and efficient worker will make E(earnings0= 160..hence it will hire all efficient people..now if it hires only efficiet people its expected profit is 540>400..hence this is profit maximizing