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Functions doubt

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Halflife
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Functions doubt

Halflife
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Halflife
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Re: Functions doubt

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Halflife
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Re: Functions doubt

Halflife
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shiva
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Re: Functions doubt

shiva
f(x) = 1/x^2 + 4, substitute -x in place of x and solve the simultaneous equations. you will get the function as above. only one function is defined with this condition and it is continous.
Halflife
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happy
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Re: Functions doubt

happy
In reply to this post by shiva
Is there any method to solve these type of question.
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