IS1-2008 ME1 answer key link

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IS1-2008 ME1 answer key link

kangkan
Hi..can someone provide the link to the answer key of isi 2008 m 1?

Thanks
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Re: IS1-2008 ME1 answer key link

bhavya jain
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Re: IS1-2008 ME1 answer key link

kangkan
Hi Bhavya..29 says limit does not exist..i am not quite able to understand why...thanks
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Re: IS1-2008 ME1 answer key link

Dreyfus
Kangkan...we r given that x is greater than 0
So when 0<x<1 then x^(-2n) would tend to infinity as n tends to infinity
When x=1 then x^(-2n) would become indeterminate as n tnds to infinity
And when x>1 then x^(-2n) would tend to 0 as n tends to infinity
Therefore no limit exist
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Re: IS1-2008 ME1 answer key link

Ridhika
The answer key says for 28.. d) decreasing in n.. whereas option d is initially increasing in n and then decreasing in n.. and a) is decreasing in n.. which is correct? and why?

Please also explain 6, 8, and 24 and 25? In 25 are we expected to integrate f(x) to get F(x) and therefore determine r(x).. or is there a shortcut.. ?
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Re: IS1-2008 ME1 answer key link

Tania123
In reply to this post by kangkan
Can someone explain Q22  please?
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Re: IS1-2008 ME1 answer key link

Dr. Strange
y= 5x^3 - 5x^2 +2x -1
dy/dx= 15x^2-10x + 2 which is always positive
 so y is strictly increasing
y(0)= -1
y(1)=1
so a root exists between 0 and 1
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Re: IS1-2008 ME1 answer key link

Tania123
@Dr. Strange. Thanks! :)