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ISI 2008 question
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RichaS
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ISI 2008 question
Please help
Abhitesh
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Re: ISI 2008 question
Integrate separately in intervals (0 to 1) --> [x]^n=0 and (1 to 2) --> [x]^n = 1
Answer will be (D) f(2)-f(1)
RichaS
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Re: ISI 2008 question
Many thanks!
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