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ISI 2011 PEA MATH

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ISI 2011 PEA MATH

saumya singha
19 posts
Q-
The number of continuous functions f satisfying
X F(Y) + Y F(X)= (X+Y)F(X) F(Y) , where x and y are any real
numbers, is

A.1
B.2
C.3
D.NONE

HOW DO WE SOLVE THIS?
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Re: ISI 2011 PEA MATH

leon
23 posts
hi saumya, what you can do is substitute x=0 and y=y.
You'll get the answer as f(x)=0 or f(x)=1.
Ans is option b.