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ISI 2011 PEA MATH
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saumya singha
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May 04, 2015; 5:30pm
ISI 2011 PEA MATH
19 posts
Q-
The number of continuous functions f satisfying
X F(Y) + Y F(X)= (X+Y)F(X) F(Y) , where x and y are any real
numbers, is
A.1
B.2
C.3
D.NONE
HOW DO WE SOLVE THIS?
leon
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May 04, 2015; 6:02pm
Re: ISI 2011 PEA MATH
23 posts
hi saumya, what you can do is substitute x=0 and y=y.
You'll get the answer as f(x)=0 or f(x)=1.
Ans is option b.
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