ISI 2015 PEA Answer Key

[nishtha92]

Thank you Akash.

On Wed, Apr 27, 2016 at 7:25 PM, Akash [via Discussion forum] <[hidden email]> wrote:

18. The domain in the second region will be a subset of first part. Thus, all its points would have been considered in first region's analysis too. So, optimum in second is less than equal to optimum in first.

14. It is given that this is true for all values of a, b,c. Thus take a=1 b=2 and c=1. The value of k evaluated from all three options will not lie between 1 and 2. Thus, none of these

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NAML

[varnika1880]

Plz help with q24

[Naveen Yadav]

Here as P(X=2)=1
E(X)=2
so, E(X-E(X))^2n= E(2-2)^2n=0

[shruti malhotra]

can someone,help me with q.20
thanks.

[Seecha]

Ques. 27 ... I m getting (c) answer

[Seecha]

How you solved question no. 30??

[Seecha]

??

[Spirit1011]

is q5 answer right? shouldnt a,b and c all should be zero?

[Spirit1011]

how to solve Q14?Consider the real valued function f x = ax^2 + bx + c )( defined on [1, 2].Then it is
always possible to get a k∈ )2,1( such that

[Janbaz Ahmed Khan]

Dear the answer i got for q14 is (a,b,c)

On 19 Apr 2017 11:28 am, "[hidden email] [via Discussion forum]" <[hidden email]> wrote:

how to solve Q14?Consider the real valued function f x = ax^2 + bx + c )( defined on [1, 2].Then it is
always possible to get a k∈ )2,1( such that

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NAML

[June]

Sir can you please provide us with  2017 sample paper answer key

[Shanky]

can anyone explain PEA  Qno. 2?