ISI ME1 2012

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ISI ME1 2012

kratika
what is the integration of 1/x over values -4 and -1?

a. ln4
b.undefined
c.ln(-4)- ln(-1)
d.none of the above

shouldn't the answer be option b bcz log is not defined over negative values?? also since d differentiation of log x gives 1/x which cannot be negative, how can we take negative values when we integrate it?? plz help!!!
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Re: ISI ME1 2012

anon_econ
integral of 1/x is |ln x|
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Re: ISI ME1 2012

neha.
I think integration of 1/x is log lxl so answer shud be -log4 which is none of the options
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Re: ISI ME1 2012

deepak
In reply to this post by anon_econ