ISI function doubt

[Halflife]

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[kanv93]

Given identity is
xf(x)+2f(-x)=-1..................(1)
multiplying it by x gives

x^2f(x)+2xf(-x)=-x.............(2)

and replacing x by -x in the the original identity and multiply it by 2 we get eq3.

(-x)f(-x)+2f(x)=-1
-2xf(-x)+4f(x)=-2................(3)


Adding eq 2 and eq3, we get
(x^2+4)f(x)=-(x+2)
=>f(x)=-(x+2)/(x^2+4)

Here numerator and denominator are continuous functions for all x and x^2+4 is not zero for any real x.Hence there exists only one  function f(x) satisfying given identity which is continuous for all x.

Need small help: Can you please share the instruction booklet for the exam. I am not able to access it. Want to be prepared on logistics etc.

Thanks in Advance!!

[Halflife]

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