or u can think of any equation like x^2-3x+2....solve it u get the zeroes as 1 and 2.....
now solve for (x-2)^2-3(x-2)+2 nd solve it u get zeroes as 3 nd 4...so in general u just need to add two to all the zeroes to get the values for second question..just always be careful about the sign..:)