JNU 2002

[neha:)]

It is observed that persons shooting at the target hit the bull's eye with probability 1/4. Which of the following events are more likely to happen?
Event E:
One person hits bull's eye at least once in four tries
Event F:
Two persons, simultaneously firing at separate targets, hit the bull's eye at the same time, at least once in 10 tries.


Please help in calculating the probability of Event F. Thanks!

[Ashima]

Atleast once in 10 times = 1- the event doesn't happen

Event is they hit the target at the same time.  

So event doesnt happen is not hitting the target at the same time = 3/4*1/4+ 3/4*3/4 + 1/4*3/4

So 1 - 15/16^10

I guess!

Please confirm!

[neha:)]

Well, it seems logical! Thanks!!

[mrittik]

right.... thanks asihma