JNU 2010

[Ayushya Kaul]

Amit Sir,
Could you please upload the solutions for JNU 2010 SSS paper if possible?

[Ayushya Kaul]

If anyone else has the solution key with them, then kindly post it in this topic :)

[Sinistral]

Dear Amit Sir,
Plz, if you could also solve the following ques for me:
http://discussion-forum.2150183.n2.nabble.com/DSE-2011-A-a-request-to-duck-Amit-Sir-Q40-plz-tp7580464p7580466.html
(i.e. ques 40)

a small hint will also suffice.

TIA

Kind Regards,
Sinistral

[Amit Goyal]

Work backwards. If you are taking the test the third time, you have to accept whatever comes. If you are taking the test the second time then you will not accept the score of below 50 because you know that rejecting it will give you a higher average score of 50. So, you will reject all scores below 50 and accept all above 50. Thus you will get average score of 75 with probability 1/2 (you only accept scores in the second test ranging from 50 to 100) and 50 with probability 1/2 (you reject scores in the second test ranging from 0 to 50 and thus will take the test the third time and get an average score of 50). So, when you are take the test for the first time and get its score your opportunity cost of accepting the first score is now (1/2)75 +(1/2)50 = 62.5. So, you will accept the first score if it exceeds 62.5 and reject otherwise.

[Sinistral]

thanx a lot :)

[sakshi]

plz explain how we get 75 with probability 1/2

[Sinistral]

This is what I understood from Sir's explanation:
expected value if we choose anything in between 50 & 100 will be 75. ( ~U(50,100)
one will get either a value in between [0,50] or [50,100] ( ~U(0,100)). so probability 1/2.

[kogo]

hey sinistral can you explain how to solve ques 40..i am not able to understand the explaination given by sir
thank you