JNU ECOM2010 ques 31-40

[Arushi :))]

QUES 36 IN an examination , there are three multiple choice questions and each question has 4 choices. Number of ways in which a student can fail to get all answers correct is
a.12
b.27
c.63
d.72
ANSWER c
QUES37 A function is selected at random from all the functions of the set A= {1,2,3........n} in to itself. The probability that the function selected one-to-one is:
a. 1/n^n
b. 2/(n-1)!
c. 1/n!
d. (n-1)!/n^(n-1)
ANSWER d
QUES38 A fair die has given the number 6 on five consecutive throws . What is the probability that the next throw will also give the number 6?
a.1/30
b. 1/6
c. 5/6
d. None of the above
ANSWER b
QUES39 The number 0.999999.... is
a. exactly equal to 1
b. slightly less than 1
c. slightly more than 1
d. between 0.99 & 0.999
ANSWER b
QUES40 Let S= 1+1/2+1/3+1/4...., Then
a. S is equal to 4
b. S is equal to 6
c. S is equal to 8.5
d. The sum doesnt converge to any finite value
ANSWER d

FOR THE QUESTIONS IN THE PICTURE
31. d
32. b
34.c
35.

[Arushi :))]

How to do 35?

[SoniaKapoor]

matched...i think for the elasticity quest answer is 1....but m not sure

[Arushi :))]

hey in hammond , its given for calculation of elasticity of f/g , we need to subtract elasticity of g from elasticity of f.
so dat way
E{f(x)/x}= E(f(x))- E(x)
We know elasticity of f(x) is 0.5 what about elasticity of a variable with respect to itself? I think it would be 1. because %change in x/ %age change in x = 1
So that way ans should be 1-0.5 = -0.5
I hope i am right :/
Btw thanks sonia... i m really happy to have found such people here :) thanku so much :)

[Arushi :))]

I am confused for 39....
between a & b

[SoniaKapoor]

for 39 ans is a
let x=.999999....    (1)
multiply by 10 both sides
10x=9.99999....      (2)
subtarct 1 from 2
9x=9
therfore x=1

[kangkan]

Matches my answers... for 35 it is -0.5 accd to me too and 39 is a(accd to wikipedia too :)

[anishagulati]

Hi
How did you calculate q36?
I am getting 27 as the answer

[Arushi :))]

36.
there are 3 questions each with 4 options.
So each question can be answered in 4 ways giving total no of ways as 4*4*4= 64
No TTT is the only way of getting all correct..
So to fail in getting all answers correct he has to choose 64-1 = 63 ways..

[Granpa Simpson]

for Q37 is the answer d...??