Maths doubt

[tanudas]

What is the domain of the function y=ln(lnx) and y= 1/[ln(lnx)-1] ?
Please help !

[Dreyfus]

[Nipun]

y=ln(lnx)

lnx > 0
Domain is x > 1 (assuming that base of log in lnx is e and if base is greater than 1, than log function is an increasing function))


y= 1/[ln(lnx)-1]

lnx > 0, --> x>1
also, ln(lnx) cannot be equal to 1. So, lnx cannot be equal to e. So, x cannot be equal to e^e.
so domain is all values of x greater than 1 except e^e, i.e.,
x = (1,infinity) - {e^e}

[tanudas]

Thanks a ton guys !

[shiva ahuja]

TEP BY STEP SOLUTION TO QUESTION OF LAST 10 YEARS OF DSE/ISI