PROBABILITY

[ahlashi]

Among 5 children there are 2 siblings
how many ways can the children be seated in a row so that siblings do not sit together

[ahlashi]

hey
sorted
thanks

[Mariyaphilip]

Total ways= 5!
The two siblings can sit among themselves in 2 ways and taken together as one, then 4 people can sit in 4! = 24 ways.
Therefore total = 120 - (24 *2) = 120 - 48 = 72 ways.