Discussion forum
›
General
›
General Discussions
Login
Register
Search
everywhere
only in this topic
Advanced Search
continuity-doubt
Classic
List
Threaded
♦
♦
Locked
5 messages
Options
Loading...
Subscribe via email
Move topic
Pin topic
Unpin topic
Lock topic
Unlock topic
Delete this topic
Delete this topic
Change title and meta tags
Embed post
Permalink
Xiang
Reply
|
Threaded
Open this post in threaded view
♦
♦
|
More
Loading...
Reply to author
Edit post
Move post
Delete this post
Delete this post and replies
Change post date
Print post
Permalink
Raw mail
Jun 06, 2013; 9:38am
continuity-doubt
let f(x)=tan(pi/4-x)/cot2x, x not equal to pi/4.
The value which should be assigned to f(x) at x-pi/4 so that it is continuous everywhere is- ?
I really dont know how to go about doing it. Please help.
thank you
cx
Reply
|
Threaded
Open this post in threaded view
♦
♦
|
More
Loading...
Edit post
Move post
Delete this post
Delete this post and replies
Change post date
Print post
Permalink
Raw mail
Jun 06, 2013; 7:00pm
Re: continuity-doubt
wat r the options!
e. Briefly,
a function f has a removable discontinuity at x = a if lim
x→a
f(x) exists and either f(a) is
undefined or lim
x→a
f(x) = f(a).
here i think we have this discontinuity so it cant be made continuous should be d ans!
Amit Goyal
Reply
|
Threaded
Open this post in threaded view
♦
♦
|
More
Loading...
Reply to author
Edit post
Move post
Delete this post
Delete this post and replies
Change post date
Print post
Permalink
Raw mail
Jun 07, 2013; 1:04am
Re: continuity-doubt
Administrator
In reply to
this post
by Xiang
f(x) at x = pi/4 should be 1/2, i.e. f(pi/4) = 1/2, for f to be continuous everywhere. Working is attached:
evaluating_limit.png
Xiang
Reply
|
Threaded
Open this post in threaded view
♦
♦
|
More
Loading...
Reply to author
Edit post
Move post
Delete this post
Delete this post and replies
Change post date
Print post
Permalink
Raw mail
Jun 07, 2013; 3:52am
Re: continuity-doubt
oh ok!
we could get answer without using the l'hospitol rule but it is a little cumbersome.
Thank you Amit sir
cx
Reply
|
Threaded
Open this post in threaded view
♦
♦
|
More
Loading...
Edit post
Move post
Delete this post
Delete this post and replies
Change post date
Print post
Permalink
Raw mail
Jun 07, 2013; 4:39pm
Re: continuity-doubt
In reply to
this post
by Amit Goyal
sorry!
i mis read the problem, basically when one gets limit equal to 0//0, one differentiates and then find the limit!
but tell me if using la hospital repeatedly we get 0/0 then will tat be called a irremovable discontinuity?
tks
Free forum by Nabble
Edit this page