doubt..

[Nikkita]

[Nikkita]

This concept was randomly used in a ques..

[Asd1995]

Define g(x) =1+f(x) and solve. It's easier that way.

Alternatively write down general form of n degree polynomial and compare coefficients on lhs and rhs of x^k, where 0<=k<=n

[Asd1995]

You can also factorise it as (1-g(x))(1-g(1/x))=1 for all x.

If f(x)=1-g(x), we get f(x) f(1/x)=1, so that f(x)=+- x^n

[Nikkita]

Thankyou Asd1995