how will we do this question-
Q57) in a survey of 400 likely voters,215 responded that they would vote for the ruling party and 185 responded that they would vote for the opposition party.let p denote the fraction of all likely voters who preferred the ruling party at the time of the survey and let p* be the fraction of survey respondents who preferred the ruling party.find standard error of p*
a) 0.025
b) 0.035
c) 0.045
d) 0.055
Let X be the people who preferred ruling party. Now X can vary from 0 to 400 ie its a rv which follows binomial distribution as there can be only two outcomes. Then p* = X/n where n=400. So p* is also follows binomial distribution with parameters p= 215/400 and q= 185/400 .
The standard error of p* = (Var(p*))½ = ((1/n²)*var(X))½
Var(x) = npq
Now ull get ur answer. Note that p* is estimator of true proportion of people who preferred ruling party!
Ok. So value of test statistic comes out to be 1.763, which is greater than 1.645( critical value for 5% one tailed test). So we accept that candidate is preferred in dist A,. Is that it?