dse question no. 27 2008, year 2007 41, 44, 45, 46, 47 year 2006 15, 52

[Kamal1]

[namrata]

2008 sum no 27 ans is c
P01=summation of(PnQ0)/summation (PoQo)=148.3
PO2=P01*P12
continuin this way for PO3 the answer is c

2007 41 is a
this is by the definition of convex set...as in chiang
44 is d..if u draw a number line startin with n=1 u will c that the intersection part corresponds to (-1,1)
45 c..continue as in the above method.
47 b use distributive property

[Chinni18]

Thanks namrata the chain index explanation  was very helpful

[Chinni18]

Hey namrata in 2008 sum no.27 in the formula for P02 where did you get P12? How do you obtain that?

[aastha]

@ chinni

P12 = summation of P2Q1/P1Q1

[Chinni18]

Thank you aastha! I finally understood properly. Been stuck on this a long time. Thanks