isi 2010 Q23

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isi 2010 Q23

eco'17
This post was updated on .
http://economicsentrance.weebly.com/uploads/1/1/0/5/1105777/msqe2010.pdf

I started this question with r(X)= P(x)/Q(x) now f(1)=1 implies P(1)=Q(1) we are suppose to find r(2)
I'm stuck here!.......please help
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Re: isi 2010 Q23

Abhitesh
We have to prove that f(x) is constant.
Let us to this by contradiction. Assume that f(x) takes two different values for different x.
Let these values be a and b(>a)
Since f(x) is continuous so it will assume all values between a and b, including the irrational ones.
Which is not possible. Thus f(x) must be constant.
i.e. f(x) =1 for all x in [0,3]
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Re: isi 2010 Q23

eco'17
thanks a lot,
I should have realized that f(x) has to be a constant.
Also, if you don't mind, can you answer Q24 as well?
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Re: isi 2010 Q23

Abhitesh
Find f(ax1, ax2) .Note to change the limit as well.
Substitute w' = w/a.
=> dw = adw'
Limits : w=0 => w'=0 ; w=a*sqrt(x1^2 + x2^2) => w' = sqrt(x1^2 + x2^2)
The integral is same as f(x1, x2). So f(ax1, ax2) = a*f(x1, x2)
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Re: isi 2010 Q23

eco'17
I'm not able to comprehend the answer, please can you explain it again.
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Re: isi 2010 Q23

Abhitesh
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Re: isi 2010 Q23

eco'17
okay I think I got it, thanks a lot!