A firm has two plants and produces a single output using two inputs. if plant 1 operates at level x1 it produces x1 units of output and utilizes 5 x1 units of input1 and 2 x1 of input2. if plant 2 operates at level x2 it produces x2 units of output and utilizes 3 x2 units of input1 and 2 x2 of input2.let y1 and y2 be level of input 1 & 2 respectively.
depict the set of inputs(y1 ,y2) that yields an o/p of 1unit..plz tell kaise banega isoquant of 1unit???
So a1=5*F1
a2 =3*F2
a1+a2=y1=5F1+3F2-----1.
Similarly b1+b2= y2= 2F1+2F2----2.
For isoquant of 1 unit: F1+F2=1-----3.
Substituting 1,2 in 3 in terms of y1,y2 you will get the equation of the isoquant.
I'm getting y2=2 as the final answer... May be I'm making some calculation error... Tell me what answer you get...
ummm firstly are we assuming zero substitutability between inputs or is it given. also isn't plant two straight-away more efficient than the first? it requires 3,2 for one unit while first requires 5,2. if so, then the second plant's isoquant should be the firm's isoquant. then min[y1/3,y2/2] is the answer (assuming no substitutability, of course).. Is this correct?
I'm not sure I understand. Can u plz help, sir?
We have 4x1+3x2=z1 and 2x1+4x2=z2. By putting x1+x2=1 i ultimately got 2z1+z2=10. also, if production takes place in both plants, 3<z1<4 and 2<z2<4. so v get the diagonal line. the end points correspond to the points at which all production takes place in only 1 plant. what next?
there is no further answer, you've derived the isoquant.. :).. the portions of the isoquant parellel to axes are where only one plant produces, the slanting line is where both produce. on the slanting portion, plant one produces z1/4 units of output and the other plant produces z2/4 units of output. am i right?
what part u nt getting...
hey in some earlier posts u said ur friend gave interview in kolkatta..can u share her experience...is the pattern same..or wat all dey asked..n the ques given to do on board was frm which topic..