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isi

seema
5 posts
pls tell me how can we solve this kind of expression?

( 11+6(2)^1/2 )^1/2 + ( 11-6(2)^1/2 )^1/2
 
Ram
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Re: isi

Ram
2 posts
Just take the square of the given term then it will be of the form (a+b)^2 here u will get it as follows
(( 11+6(2)^1/2 )^1/2 + ( 11-6(2)^1/2 )^1/2)^2= 11+6(2)^1/2+11-6(2)^1/2+2(11^2-(6(2)^1/2)^2)=22+2(49)^1/2=22+14=36 now just take the square root of it which is 6....
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Re: isi

seema
5 posts
thanx ram. :)
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Re: isi

ritu
43 posts
wot answer do u get  for this questn then....seema...its isi 2012 question 16?????
s
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Re: isi

s
86 posts
yeah isi 2012 no 16 , 6 is a positive and even integer