isi

[seema]

pls tell me how can we solve this kind of expression?

( 11+6(2)^1/2 )^1/2 + ( 11-6(2)^1/2 )^1/2
 

[Ram]

Just take the square of the given term then it will be of the form (a+b)^2 here u will get it as follows
(( 11+6(2)^1/2 )^1/2 + ( 11-6(2)^1/2 )^1/2)^2= 11+6(2)^1/2+11-6(2)^1/2+2(11^2-(6(2)^1/2)^2)=22+2(49)^1/2=22+14=36 now just take the square root of it which is 6....

[seema]

thanx ram. :)

[ritu]

wot answer do u get  for this questn then....seema...its isi 2012 question 16?????

[s]

yeah isi 2012 no 16 , 6 is a positive and even integer