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for 0 < x < 1, log x < 0 < x
for x = 1, log x = 0 < 1
for x > 1, f(x) = x - log x is an increasing function (because f'(x) = 1 - 1/x > 0) and we know that f(x) is continuous everywhere on (0, ∞). Thus, f(1) > 0 and f'(x) > 0 implies that f(x) > 0 for x > 1.
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