mathematics problem

[chirag]

Question 1) - Let Pn=[((2^3)-1)/((2^3)+1)]*[((3^3)-1)/((3^3)+1)]*....*[((n^3)-1)/((n^3)+1)] for n=2,3,4,......
Find the limit of Pn when n tends to infinity
A)3/4   B)7/11  C)2/3   D)1/2

[Abhitesh]

Pn can be written as
7/9 * 26/28 * 63/65 * 124/126 * 215/217 * ...
= 1.7/3.3 * 2.13/4.7 * 3.21/5.13 * 4.31/6.21 * 5.43/7.31 * ...

After cancellation Pn = 2/3

[chirag]

Sir got it what you did, but can you please explain.

[chirag]

Followed your answer sir Thank you. No need to explain.