Hi Ritu.. :)
1) Probability that not all squares in any column are alternating in color= [1-1/2^7]^8
{First, try to find out the probability in which you can color a column such that they alternate in color}
2)Probability that chess board contains equal number of red and black squares = 64!/32!*32!*2^64
{Find out the favorable number of cases}
3)Probability that all squares in any column are of same color and alternating color in any row= 1/2^63
{There are only two ways in this case}
Note: Do the same problem in case of 2*2 or 4*4 chessboard.
:)
:)