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Var1995
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probability
we will use baye's thm to solve this?
can someone solve it here?
Dr. Strange
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Re: probability
P(X1=2|X2=1)=P(X2=1|X1=2)*P(X1=2)/P(X2=1) ...BAYES THEOREM
NOW P(X2=1|X1=2)=0.5
P(X1=2)=0.5
P(X2=1|X1=1)=1
P(X2=1)= P(X2=1|X1=1)*P(X1=1) + P(X2=1|X1=2)*P(X1=2) =0.75
SO ANSWER IS 1/3
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