Re: 2008 q 51, 2005 q 23 and 2004 q 30

Posted by Khushboo on Jun 02, 2009; 2:35am
URL: http://discussion-forum.276.s1.nabble.com/2008-q-51-2005-q-23-and-2004-q-30-tp3009651p3010097.html

Ans -30  2004 paper
          P(x2>1) = P(x>1 or X<-1)
                     = P(x>1) + P(x<-1)
                     = P+P = 2P
          P(y3 >1)= P(y>1) = p
  Therefore, P(x2>1 and y3 >1) = 2P.P = 2p2