Re: Problem Code: 210609MATH

Posted by PRANAVjain on
URL: http://discussion-forum.276.s1.nabble.com/Problem-Code-210609MATH-tp3126561p4808649.html

HOW THE PROBABILITY COMES OUT TO BE 1/9?
P(F/3 HEADS)=P(F n 3 HEADS)/P(3 HEADS)
{n MEANS INTERSECTION}

IS THIS THE WAY TO SOLVE IT?