Re: Problem Code: 210609MATH

Posted by duck on Mar 29, 2010; 11:57am
URL: http://discussion-forum.276.s1.nabble.com/Problem-Code-210609MATH-tp3126561p4817509.html

hi pranav, it can be solved in the following way>>

let, Fair coin be "F"
unfair coin be "U"
and 3 heads be "3H"

P(F)=1/2 , P(U)=1/2

P(3H/f)=1/2 * 1/2 * 1/2 = 1/8

P(3h/U)=1*1*1= 1

NOW,
P(F/3H)= P(3H/F)* P(F)
            --------------
             P(3H/F)* P(F) + P(3H/U)* P(U)

           =     (1/8* 1/2)
             ---------------
            (1/8*1/2)+ (1*1/2)

          =1/9