Re: Maths

Posted by duck on Apr 03, 2010; 1:36pm
URL: http://discussion-forum.276.s1.nabble.com/Maths-tp4846088p4846982.html

Hi Shweta,

It can be solved in the following way>>

Let denote processor 1 by "I" and processor2 by "II" , Computer by "C"
P(I)=3/4    => P(I')=1/4
P(II)=7/8   => P(II')=1/8

NOW, P(C)=processor one works or processor two works or both processors work.
 
=>P(C)=3/4* 1/8 + 7/8 * 1/4 + 3/4 * 7/8
       
          =31/32
Also, P(computer is funtional given processor1 is working)= 3/4* 1/8 + 3/4*7/8
                                                                             =24/32

Therefore,

P(processor1 is working given computer is functional)= P(computer is funtional given processor1 is working)
                                                                        ---------------------------------------------------
                                                                                     P(C)

                                                          = 24/32
                                                           -------
                                                             31/32

                                                           = 24/32