Re: Sample Questions of ISI ME I (Mathematics) 2010 Discussion

Posted by N Uday Kumar on Apr 04, 2010; 8:19pm
URL: http://discussion-forum.276.s1.nabble.com/Sample-Questions-of-ISI-ME-I-Mathematics-2010-Discussion-tp4850019p4851110.html

1/[n*(n+1)] can be written as [1/n - 1/(n+1)]
i.e. 1/(1*2) = 1 - 1/2
      1/(2*3) = 1/2 - 1/3
      .
      .
      .
      1/(99*100) = 1/99 - 1/100