Re: dse-2009

Posted by Swati jain on Jun 24, 2010; 3:56pm
URL: http://discussion-forum.276.s1.nabble.com/dse-2009-tp5196723p5218344.html

total no.of cases wud be 9*8*7*6*5*4*3*2*1
take 123 as fixed places and rest can be filled by 6*5*4*3*2*1
123 can be placed in the starting or last or in between so like this v hv 7 cases.
probability = 7*6*5*4*3*2*1/9*8*7*6*5*4*3*2*1    =1/72