Re: ISI 2011 SAMPLE PAPER ME 1 DISCUSSIONS

Posted by sachin on May 06, 2011; 7:41pm
URL: http://discussion-forum.276.s1.nabble.com/ISI-2011-SAMPLE-PAPER-ME-1-DISCUSSIONS-tp6171801p6338673.html

h'(x)= f'(g(x))g'(x)=(-)(+)= (-) so always decreasing.
h(0)=0
>>>>h(x)< 0 for all x
for x<1
>>>>h(x)>h(1) for all x less than 1.....since f is decreasing
>>>>h(x)-h(1)>0 for all than 1

but for x>1
>>>>>h(x)<h(1)
>>>>>h(x)-h(1)<0

hence..a is ans..
note: add equality sign to all inequality...